Q. The map distance between genes A and B is 3 units, between B and C 10 units and between C and A 7 units. The order of the genes in a linkage map constructed on the above data would perhaps be :

Q. The map distance between genes A and B is 3 units, between B and C 10 units and between C and A 7 units. The order of the genes in a linkage map constructed on the above data would perhaps be :

Q. The map distance between genes A and B is 3 units, between B and C 10 units and between C and A 7 units. The order of the genes in a linkage map constructed on the above data would perhaps be :

(a) A, B, C

(b) A, C, D

(c) B, C, A

(d) B, A, C

Solution :

Correct option : D Distance between A and B is 3 units. Between B and C is 10 units. Between C and A is 7 units. So it can be marked as :
B A C
|————|————————-|
3 Units 7 units

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